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07-Sep-2018 16:20

Try to phrase the problem in a more mathematical way.Are there lesbians in this problem or is this the "Gay male speed dating problem"?Then again, I figure if everyone in the dating schematic is gay, the two-gender case reduces to a maximum of the separate one-gender cases, so it's not really a problem [email protected] Yuan: I think he means counting the number of maximal sets of disjoint edges in a complete graph on $n$ vertices. With 3 people, you need 3 rounds (because everyone has to sit out a round), not 2.I think I encountered something like this problem (including the proper terminology) in a graph theory textbook once, but I don't have easy access to it at the moment. With 6 people with your method, you seem to require 3=6$ rounds, but it is possible with 5 rounds, as the OP says. The technical term for what Ross has done (in the even case) is finding a 1-factorization of the complete graph on n$ vertices - see, e.g., en.wikipedia.org/wiki/Graph_factorization The odd case is the same as math.stackexchange.com/questions/54846/…Speed Dating – такой формат вечеринок быстрых знакомств появился в конце прошлого века в США и быстро стал популярен и в Европе.Корреспондент журнала «Гламур» Ольга Любимова посетила вечеринку от компании Fast Life...

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